-- =============================================================================
-- app_icon 版本号 / 生效状态 存量数据修复脚本
--
-- 背景：
--   旧逻辑用「当前生效版本 + 1」生成版本号，无当前生效记录时固定用 1；
--   而删除是逻辑删除（is_deleted=1），且唯一索引 uk_package_version(package_name, version)
--   不包含 is_deleted。当前生效记录被删除或缺失时，再次上传就会撞唯一键：
--     Duplicate entry 'com_alibaba_android_rimet-1' for key 'app_icon.uk_package_version'
--
-- 新逻辑：
--   version = 该 package_name 下所有记录（含 is_deleted=1）的 MAX(version) + 1，
--   版本号只增不减、永不复用；上传 / 锁定已按包名加锁并置于同一事务内。
--
-- 使用说明：
--   1. 本脚本仅用于「已在运行、不重建表」的库；全新部署执行 app_icon.sql 即可。
--   2. 由 DBA 在业务低峰期单独执行，执行前请备份 app_icon 表。
--   3. 诊断语句（第 1 ~ 3 段）先执行确认现状，再执行修复语句（第 4 ~ 5 段）。
-- =============================================================================

-- -----------------------------------------------------------------------------
-- 1. 诊断：同一包名存在多条 status=1（会导致 one() 抛 TooManyResultsException）
-- -----------------------------------------------------------------------------
SELECT package_name, COUNT(*) AS active_cnt
FROM app_icon
WHERE is_deleted = 0
  AND status = 1
GROUP BY package_name
HAVING COUNT(*) > 1;

-- -----------------------------------------------------------------------------
-- 2. 诊断：同一包名有未删除记录，但没有任何 status=1（上传会走「无当前版本」分支）
-- -----------------------------------------------------------------------------
SELECT package_name, COUNT(*) AS alive_cnt, MAX(version) AS max_version
FROM app_icon
WHERE is_deleted = 0
GROUP BY package_name
HAVING SUM(status = 1) = 0;

-- -----------------------------------------------------------------------------
-- 3. 诊断：查看具体包名的版本与删除残留
-- -----------------------------------------------------------------------------
SELECT id, package_name, version, status, locked, is_deleted, update_time
FROM app_icon
WHERE package_name = 'com_alibaba_android_rimet'
ORDER BY is_deleted, version;

-- -----------------------------------------------------------------------------
-- 4. 修复多条 status=1：保留 version 最大的一条为当前生效，其余置为历史
-- -----------------------------------------------------------------------------
UPDATE app_icon a
    JOIN (SELECT package_name, MAX(version) AS max_version
          FROM app_icon
          WHERE is_deleted = 0
            AND status = 1
          GROUP BY package_name) t
    ON a.package_name = t.package_name
SET a.status = 0,
    a.update_time = NOW()
WHERE a.is_deleted = 0
  AND a.status = 1
  AND a.version < t.max_version;

-- -----------------------------------------------------------------------------
-- 5. 修复无 status=1：把未删除记录里版本号最大的一条置为当前生效
-- -----------------------------------------------------------------------------
UPDATE app_icon a
    JOIN (SELECT package_name, MAX(version) AS max_version
          FROM app_icon
          WHERE is_deleted = 0
          GROUP BY package_name
          HAVING SUM(status = 1) = 0) t
    ON a.package_name = t.package_name
        AND a.version = t.max_version
SET a.status = 1,
    a.update_time = NOW()
WHERE a.is_deleted = 0;

-- -----------------------------------------------------------------------------
-- 6. 复核：两条诊断语句均应返回空结果集
-- -----------------------------------------------------------------------------
SELECT package_name, COUNT(*) AS active_cnt
FROM app_icon
WHERE is_deleted = 0
  AND status = 1
GROUP BY package_name
HAVING COUNT(*) > 1;

SELECT package_name, COUNT(*) AS alive_cnt
FROM app_icon
WHERE is_deleted = 0
GROUP BY package_name
HAVING SUM(status = 1) = 0;