feat(device): 应用图标改存云存储并修复版本号唯一键冲突

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tongtong committed 2026-10-19 14:35:27 +08:00
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-- =============================================================================
-- app_icon 版本号 / 生效状态 存量数据修复脚本
--
-- 背景:
-- 旧逻辑用「当前生效版本 + 1」生成版本号,无当前生效记录时固定用 1;
-- 而删除是逻辑删除(is_deleted=1),且唯一索引 uk_package_version(package_name, version)
-- 不包含 is_deleted。当前生效记录被删除或缺失时,再次上传就会撞唯一键:
-- Duplicate entry 'com_alibaba_android_rimet-1' for key 'app_icon.uk_package_version'
--
-- 新逻辑:
-- version = 该 package_name 下所有记录(含 is_deleted=1)的 MAX(version) + 1,
-- 版本号只增不减、永不复用;上传 / 锁定已按包名加锁并置于同一事务内。
--
-- 使用说明:
-- 1. 本脚本仅用于「已在运行、不重建表」的库;全新部署执行 app_icon.sql 即可。
-- 2. 由 DBA 在业务低峰期单独执行,执行前请备份 app_icon 表。
-- 3. 诊断语句(第 1 ~ 3 段)先执行确认现状,再执行修复语句(第 4 ~ 5 段)。
-- =============================================================================
-- -----------------------------------------------------------------------------
-- 1. 诊断:同一包名存在多条 status=1(会导致 one() 抛 TooManyResultsException)
-- -----------------------------------------------------------------------------
SELECT package_name, COUNT(*) AS active_cnt
FROM app_icon
WHERE is_deleted = 0
AND status = 1
GROUP BY package_name
HAVING COUNT(*) > 1;
-- -----------------------------------------------------------------------------
-- 2. 诊断:同一包名有未删除记录,但没有任何 status=1(上传会走「无当前版本」分支)
-- -----------------------------------------------------------------------------
SELECT package_name, COUNT(*) AS alive_cnt, MAX(version) AS max_version
FROM app_icon
WHERE is_deleted = 0
GROUP BY package_name
HAVING SUM(status = 1) = 0;
-- -----------------------------------------------------------------------------
-- 3. 诊断:查看具体包名的版本与删除残留
-- -----------------------------------------------------------------------------
SELECT id, package_name, version, status, locked, is_deleted, update_time
FROM app_icon
WHERE package_name = 'com_alibaba_android_rimet'
ORDER BY is_deleted, version;
-- -----------------------------------------------------------------------------
-- 4. 修复多条 status=1:保留 version 最大的一条为当前生效,其余置为历史
-- -----------------------------------------------------------------------------
UPDATE app_icon a
JOIN (SELECT package_name, MAX(version) AS max_version
FROM app_icon
WHERE is_deleted = 0
AND status = 1
GROUP BY package_name) t
ON a.package_name = t.package_name
SET a.status = 0,
a.update_time = NOW()
WHERE a.is_deleted = 0
AND a.status = 1
AND a.version < t.max_version;
-- -----------------------------------------------------------------------------
-- 5. 修复无 status=1:把未删除记录里版本号最大的一条置为当前生效
-- -----------------------------------------------------------------------------
UPDATE app_icon a
JOIN (SELECT package_name, MAX(version) AS max_version
FROM app_icon
WHERE is_deleted = 0
GROUP BY package_name
HAVING SUM(status = 1) = 0) t
ON a.package_name = t.package_name
AND a.version = t.max_version
SET a.status = 1,
a.update_time = NOW()
WHERE a.is_deleted = 0;
-- -----------------------------------------------------------------------------
-- 6. 复核:两条诊断语句均应返回空结果集
-- -----------------------------------------------------------------------------
SELECT package_name, COUNT(*) AS active_cnt
FROM app_icon
WHERE is_deleted = 0
AND status = 1
GROUP BY package_name
HAVING COUNT(*) > 1;
SELECT package_name, COUNT(*) AS alive_cnt
FROM app_icon
WHERE is_deleted = 0
GROUP BY package_name
HAVING SUM(status = 1) = 0;