93 lines
4.0 KiB
SQL
93 lines
4.0 KiB
SQL
-- =============================================================================
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-- app_icon 版本号 / 生效状态 存量数据修复脚本
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--
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-- 背景：
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-- 旧逻辑用「当前生效版本 + 1」生成版本号，无当前生效记录时固定用 1；
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-- 而删除是逻辑删除（is_deleted=1），且唯一索引 uk_package_version(package_name, version)
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-- 不包含 is_deleted。当前生效记录被删除或缺失时，再次上传就会撞唯一键：
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-- Duplicate entry 'com_alibaba_android_rimet-1' for key 'app_icon.uk_package_version'
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--
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-- 新逻辑：
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-- version = 该 package_name 下所有记录（含 is_deleted=1）的 MAX(version) + 1，
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-- 版本号只增不减、永不复用；上传 / 锁定已按包名加锁并置于同一事务内。
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--
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-- 使用说明：
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-- 1. 本脚本仅用于「已在运行、不重建表」的库；全新部署执行 app_icon.sql 即可。
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-- 2. 由 DBA 在业务低峰期单独执行，执行前请备份 app_icon 表。
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-- 3. 诊断语句（第 1 ~ 3 段）先执行确认现状，再执行修复语句（第 4 ~ 5 段）。
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-- =============================================================================
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-- -----------------------------------------------------------------------------
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-- 1. 诊断：同一包名存在多条 status=1（会导致 one() 抛 TooManyResultsException）
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-- -----------------------------------------------------------------------------
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SELECT package_name, COUNT(*) AS active_cnt
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FROM app_icon
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WHERE is_deleted = 0
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AND status = 1
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GROUP BY package_name
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HAVING COUNT(*) > 1;
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-- -----------------------------------------------------------------------------
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-- 2. 诊断：同一包名有未删除记录，但没有任何 status=1（上传会走「无当前版本」分支）
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-- -----------------------------------------------------------------------------
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SELECT package_name, COUNT(*) AS alive_cnt, MAX(version) AS max_version
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FROM app_icon
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WHERE is_deleted = 0
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GROUP BY package_name
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HAVING SUM(status = 1) = 0;
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-- -----------------------------------------------------------------------------
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-- 3. 诊断：查看具体包名的版本与删除残留
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-- -----------------------------------------------------------------------------
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SELECT id, package_name, version, status, locked, is_deleted, update_time
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FROM app_icon
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WHERE package_name = 'com_alibaba_android_rimet'
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ORDER BY is_deleted, version;
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-- -----------------------------------------------------------------------------
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-- 4. 修复多条 status=1：保留 version 最大的一条为当前生效，其余置为历史
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-- -----------------------------------------------------------------------------
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UPDATE app_icon a
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JOIN (SELECT package_name, MAX(version) AS max_version
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FROM app_icon
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WHERE is_deleted = 0
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AND status = 1
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GROUP BY package_name) t
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ON a.package_name = t.package_name
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SET a.status = 0,
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a.update_time = NOW()
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WHERE a.is_deleted = 0
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AND a.status = 1
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AND a.version < t.max_version;
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-- -----------------------------------------------------------------------------
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-- 5. 修复无 status=1：把未删除记录里版本号最大的一条置为当前生效
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-- -----------------------------------------------------------------------------
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UPDATE app_icon a
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JOIN (SELECT package_name, MAX(version) AS max_version
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FROM app_icon
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WHERE is_deleted = 0
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GROUP BY package_name
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HAVING SUM(status = 1) = 0) t
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ON a.package_name = t.package_name
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AND a.version = t.max_version
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SET a.status = 1,
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a.update_time = NOW()
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WHERE a.is_deleted = 0;
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-- -----------------------------------------------------------------------------
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-- 6. 复核：两条诊断语句均应返回空结果集
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-- -----------------------------------------------------------------------------
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SELECT package_name, COUNT(*) AS active_cnt
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FROM app_icon
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WHERE is_deleted = 0
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AND status = 1
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GROUP BY package_name
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HAVING COUNT(*) > 1;
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SELECT package_name, COUNT(*) AS alive_cnt
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FROM app_icon
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WHERE is_deleted = 0
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GROUP BY package_name
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HAVING SUM(status = 1) = 0;
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